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Fifth Powers (Posted on 2023-03-21) Difficulty: 3 of 5
Find all solutions of:

x^5+y^5=(x+y)^5

Assume x>y.

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts computer exploration | Comment 1 of 3
When either x or y is zero or y = -x, the equation is true.

Other than these, the program 

clc
for y=sym(-200):200
  for x=y+1:200
    if x^5+y^5==(x+y)^5 && x*y~=0 && x~=-y
      disp([x y])
    end
  end
end

finds no other instances.

Of course this is not an exhaustive search.

  Posted by Charlie on 2023-03-21 09:48:42
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