perplexus.info :: Just Math : Function of a function

Function of a function (Posted on 2023-04-14)

f(f(x))=x^2-x+1

Evaluate f(0)

No Solution Yet Submitted by Ady TZIDON

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Solution

| Comment 2 of 4 |

f(f(x)) = (x^2-x+1)^2 - (x^2-x+1) + 1

= [x^4 -2x^3 - x^2 + 2x + 1] - [x^2-x+1] + 1

= 1 - 1 + 1

= 1

Posted by hoodat on 2023-04-16 00:46:44

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