Two people (A and B) want to meet each other to have lunch, and plan to meet at B's house party. A starts out for B's house, but when A is a mile away from B's house, B realizes that his house is a mess and A's isn't. So B takes off to meet A.

Once they meet, they talk for a while, and decide to meet at A's house instead. A goes back to her house to wait for B, and B goes to his house to pick up his food, then goes to A's house. They arrive at A's house at exactly the same time. If B walks twice as fast as A, how far apart do the two people live?

(In reply to it is a try by ben)

That's what I thought at first too, until I re-read the problem. They don't meet 1 mile from B's house. It's that when A is 1 mile from B's house, that's when B just leaves his house. They meet somewhere in between and then both start walking. When A gets BACK to the 1 mile mark, B just arrived back at his home before turning around to go to A's house.

Posted by nikki on 2003-10-30 11:24:53