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Find Last 3 Digits (Posted on 2024-02-20) Difficulty: 3 of 5
Find the last three digits of the product of the positive roots of:

3√(2021)* Xlog2021X = X3

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Solution Analytic Solution Comment 4 of 4 |
Start by taking log_2021 on both sides.  That yields:
(1/3) + log_2021(x)*log_2021(x) = 3*log_2021(x)

For brevity, let L=log_2021(x).  Then the last equation can be rewritten as 3L^2 - 9L + 1 = 0.

Then the quadratic formula yields L = (9+sqrt(69))/6 or (9-sqrt(69))/6.  
Then x = 2021^(9+sqrt(69))/6 or 2021^(9-sqrt(69))/6

The product of these solutions for x is 
[2021^(9+sqrt(69))/6] * [2021^(9-sqrt(69))/6] 
= 2021^[(9+sqrt(69))/6 + (9-sqrt(69))/6] 
= 2021^3 = 8254655261.

The last three digits of the product of the roots are 261.

  Posted by Brian Smith on 2024-02-20 11:10:09
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