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Symmetric expressions (Posted on 2023-09-13) Difficulty: 2 of 5
Let a, b, c, x, y and z be numbers such that a=(b+c)/(x-2), b=(c+a)/(y-2), c=(a+b)/(z-2). If xy+yz+zx=1000 and x+y+z=2016, find the value of xyz.

No Solution Yet Submitted by Danish Ahmed Khan    
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  Subject Author Date
Some Thoughtsmy takeJer2023-09-14 10:09:00
Questionbroll2023-09-14 01:30:24
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