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| Symmetric expressions (Posted on 2023-09-13) |
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Let a, b, c, x, y and z be numbers such that
a=(b+c)/(x-2), b=(c+a)/(y-2), c=(a+b)/(z-2). If xy+yz+zx=1000 and x+y+z=2016, find the value of xyz.
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 | my take | Jer | 2023-09-14 10:09:00 |
 | Question | broll | 2023-09-14 01:30:24 |
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