All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Four Powers (Posted on 2023-08-10) Difficulty: 1 of 5
8^a+2^b+16^c+2^d=660

Find (a,b,c,d)

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution solution | Comment 1 of 2
660, expressed in binary, is  1010010100. The on-bits represent powers of 2 that are: 2, 4, 7 and 9.  The bases of the powers given in the puzzle are 1, 4, 1 again, and 3.

Now, the 9 that we need is a multiple of the 3 we have already, so a could be 3 as 8^3 is 2^9 = 512.

The 4 that we need is already there, as 16; just make c = 1.

The 2 and the 7 need be assigned; either b is 2 and d is 7 or vice versa.

(a, b, c, d) = (3, 2, 1, 7) or

(a, b, c, d) = (3, 7, 1, 2)

  Posted by Charlie on 2023-08-10 08:32:04
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information