perplexus.info :: Just Math : Maximum of divisor contraints

Maximum of divisor contraints (Posted on 2023-12-07)

Positive integers a,b are such that 137 divides a+139b and 139 divides a+137b. Find the minimum possible value of a+b.

No Solution Yet Submitted by Danish Ahmed Khan

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Puzzle Answer

| Comment 2 of 3 |

Minimum value of a=275

Minimum value of b = 68

Therefore, the minimum value of a+b= 275+68= 343

Posted by K Sengupta on 2023-12-08 00:55:33

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