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Capped down sequence (Posted on 2024-01-20) Difficulty: 3 of 5
Let xn be a sequence defined by x1=1 and xn+1=3xn+[xn√5] for all n=1,2,3... where [x] denotes the greatest integer that does not exceed x. Prove that for any positive integer n we have xnxn+2−x2n+1=4n-1
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No Solution Yet Submitted by Danish Ahmed Khan    
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