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Red and Blue chips (Posted on 2024-01-28) Difficulty: 2 of 5
Jane and Fred each have their own collection of red and blue bingo chips. The ratio of the number of Jane’s chips to the number of Fred’s chips is 3:2. When they combine their chips, the ratio of the number of red chips to the number of blue chips is 7:3. For Jane’s chips, the ratio of the number of red chips to the number of blue chips is 4:1.

What is the ratio of the number of red chips to the number of blue chips for Fred’s bingo chips?

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Puzzle Solution | Comment 2 of 3 |
#Jane's chips= 3x, #Fred's chips = 2x
# Red Chips = 7y, # Blue chips = 3y
# Jane's Red Chips = 4z, # Jane's Blue chips = z
Total # chips = 5x = 10y
=> x= 2y
Therefore, #Jane's chips = 6y, # Fred's chips = 4y
#Jane's chips = 5z= 6y
 => z = 6k, y = 5k
Accordingly, 
#Fred's Blue chips = Total # Blue chips - Jane's Blue chips = 3y - z = 3*5k - 6k = 9k
#Fred's Red chips = Total # Red chips - Jane's Red Chips = 7y- 4z = 7*5k - 4*6k = 35k - 24k = 11k
Consequently, the required ratio = 11k:9k == 11:9

  Posted by K Sengupta on 2024-01-28 12:59:13
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