 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Tricky Triangle (Posted on 2003-12-03) Replace the letters in the diagram with a different number from 0 to 9, such that the sum of the four numbers on all edges are the same, and the sum of the three numbers on all three corners are the same.
```          A
B   C
D   E   F
G   H   I   J
```

In other words, A+C+F+J = A+B+D+G = G+H+I+J and
A+B+C = D+G+H = F+I+J.

 No Solution Yet Submitted by Kelsey Rating: 3.2500 (4 votes) Comments: ( Back to comment list | You must be logged in to post comments.) Solution Comment 15 of 15 | If we include rotations and reflections, there are twelve solutions. The two basic solutions are:

1          Each corner sums to 13.
5 7         Each edge sums to 19.
4 6 3        Center number is 6.

9 0 2 8

1          Each corner sums to 14.

6 7         Each edge sums to 17.
2 3 9        Center number is 3.
8 4 5 0

The twelve solutions:

ABCDEFGHIJ  ABCDEFGHIJ
0594378261  1574639028
0957341628  1753648209
1672398450  8230679451
1769320548  8327601549
8246351790  9042658371
8425360971  9405621738

 Posted by Dej Mar on 2008-03-21 15:59:15 Please log in:

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