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Tricky Triangle (Posted on 2003-12-03) Difficulty: 4 of 5
Replace the letters in the diagram with a different number from 0 to 9, such that the sum of the four numbers on all edges are the same, and the sum of the three numbers on all three corners are the same.
          A
        B   C
      D   E   F
    G   H   I   J

In other words, A+C+F+J = A+B+D+G = G+H+I+J and
A+B+C = D+G+H = F+I+J.

No Solution Yet Submitted by Kelsey    
Rating: 3.2500 (4 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionDej Mar2008-03-21 15:59:15
re(2): answerK Sengupta2008-03-21 12:35:22
re: answerJayDeeKay2008-03-20 17:26:13
answerK Sengupta2007-06-20 09:49:22
oops wrong,i forgot the bottom row!!! :(John2004-02-17 13:10:39
SolutionsolutionJohn2004-02-17 13:07:12
re: check it outchris Knight2003-12-03 20:04:27
Solutioncheck it outchris Knight2003-12-03 20:01:49
Solutionre(2): Multiple solutions.--down to twoCharlie2003-12-03 14:12:03
re: wording changeFederico Kereki2003-12-03 13:11:19
re: wording changeBrian Smith2003-12-03 11:45:15
wording changeCory Taylor2003-12-03 11:31:00
SolutionFull solutionFederico Kereki2003-12-03 10:54:12
re: Multiple solutions.wonshot2003-12-03 10:36:03
SolutionMultiple solutions.Charlie2003-12-03 10:27:56
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