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Sum of Cubes (Posted on 2004-05-25) Difficulty: 3 of 5
Prove that the sum of consecutive perfect cubes (starting with 1) is always a perfect square.

For example:
1=1
1+8=9
1+8+27=36

See The Solution Submitted by Gamer    
Rating: 3.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution | Comment 9 of 12 |
1³+2³+3³+....n³=(n(n+1)/2)²
As n(n+1)/2 is always an integer, the given sum is always a perfect square.

  Posted by Praneeth on 2007-08-14 00:55:25
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