Given a square piece of paper, show how by creasing and folding only, a square of half the area of the original can be obtained.
(In reply to
re: Variation: by Jer)
A couple of clarifications:
Re:
Call the small creases perpendicular to AB and AD 'X' and 'Y' respectively. AO = AX = AY = .52.
A whole line segment has been labeled X and another Y, but the next equation treats X and Y as points. Actually you want to call the points where the small creases perpendicular to AB and AD meet the edges of the paper X and Y respectively.
Re:
6. Fold DC up so that D is on AY and C is on BC.
This does not specify how far along AY that D should be placed. It should be placed far enough that the fold itself includes point Y. Likewise for the next fold, which is to include point X.

Posted by Charlie
on 20040408 11:08:44 