Is it possible to get a perfect square if you multiply three consecutive natural numbers?

(In reply to Solution by Penny)

Taking 999799 * 999800 * 999801 = (999700015)^2, the left hand side ends in 0, while the right hand side ends in 5, so the two cannot be equal.  Similary for the other results.  I think you are running up against the limits of accuracy for doubles.

Posted by Nick Hobson on 2004-06-26 13:16:42