All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Buric's Cube (Posted on 2004-12-22)
 Professor Buric likes to set his students logic problems using eight normal dice in a 2󫎾 cube as shown here. Let the six faces of the cube be referred to as: ```ABFE - TOP ABCD - FRONT DCGH - BASE EFGH - BACK AEHD - LEFT BFGC - RIGHT```
Each of the six faces shows four numbers and three faces of one die are seen at each of the eight corners of the cube. The Professor then makes several statements regarding the viewable numbers and challenges the students to place all twenty four visible numbers in their correct positions in 40 minutes or less.

On one occasion the following clues were given:

1. All six faces show four different numbers but each of the numbers 1, 2, 3, 4, 5, and 6 appear four times.
2. The numbers on the front can be arranged to make a four-digit square number, and those on the back can form a different four-digit square.
3. The sum of the numbers showing on the top is the same total as those on the base.
4. The numbers showing at corner F are 2, 3, and 6.
5. The numbers seen on the front are consecutive, but not necessarily in order.
6. Three odd numbers form corner B, and the product of all the numbers on the top is 180.
7. At corner G, the sum of the numbers is only 7, while at corner E, only even numbers are seen, and each of these is either the largest or smallest number seen on its face.
8. The numbers on the right side do not include a 6, and only one 5 appears in the top half of the cube.
9. At corner C, one of the numbers equals the sum of the other two.
Knowing that the dice need not be identical, as the only rule governing the positions of the numbers on these dice is that opposite faces add up to seven, can you graduate from the Professor's class?

 No Solution Yet Submitted by SilverKnight Rating: 4.2222 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 And the answer is... Comment 7 of 7 |

My answer to the question posed is "No.  I can't graduate from Professor Buric's class?

Is that good enough, or does this type of problem require further elaboration?  If so, here goes:  I could not complete the task within 40 minutes.  It took me 30 minutes to digest the conditions and understand the problem, then another 2 minutes to put the eight dice together only to find out I half of my dice were of the wrong type.  Charlie and DJ passed the class because they split the task into two parts, and each had complementary dice, so they swapped four each.

I was also distracted by RandyOrton.  He was running around with scissors (in the wrong hand, I might add.)  At least I wasn't alone.  Hugo and nikki failed the class last year for similar reasons.  When will the Full Solution be posted?

 Posted by Mindy Rodriguez on 2005-11-23 00:26:12

 Search: Search body:
Forums (0)