Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
I am going gto do this in parts because it takes so long to get this typed, I get kicked out, then lose my post...
Draw another triangle copy of ABC, such that AD is the base of the new triangle. Apex of new triangle is E.
We know angles C and B are 80 degrees, so new angle at A is 100. AE is equal to AB, so angle E and new B are 40.
More to come....
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Posted by Jim
on 2004-09-09 14:15:38 |
first part
