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Division (Posted on 2004-12-11) Difficulty: 3 of 5
For which positive integer values of N is 2^N-1 a multiple of N?

See The Solution Submitted by e.g.    
Rating: 3.8333 (6 votes)

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no parentheses | Comment 5 of 16 |
As far as whether it is 2^(N-1) or (2^N) - 1:

since there are no parentheses, I would assume that the usual order of operations applies.  Since exponentiation is 'stronger' than subtraction, then I assume it to be: (2^N) - 1
  Posted by Larry on 2004-12-12 08:20:22
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