(x+y)^z+(y+z)^x+(z+x)^y > 2.
Yes, you are wrong. Let x=1/2, y=1/4, and z=1/8. Then S= 2.466190771 and 3*(2z)^z=2.522689246 (which is less than 3, also). Your inequality has problems when the values are less than 1, since (1/2)^(1/4) > (1/2)^(1/2) for example.
blackjack
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flooble's webmaster puzzle
re: am I wrong ?
