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Squaring sides (Posted on 2005-05-04) Difficulty: 4 of 5
Take any convex quadrilateral ABCD, with diagonals AC and BD. Pick E so ABCE is a parallelogram. Prove that AB+BC+CD+DA= AC+BD+DE.

Given the same quadrilateral, let P and Q be the midpoints of AC and BD. Now prove that AB+BC+CD+DA= AC+BD+4PQ.

See The Solution Submitted by Federico Kereki    
Rating: 4.0000 (2 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: The analytic geometry way (part 1 only)nikki2005-05-06 12:31:16
The analytic geometry way (part 1 only)Jer2005-05-05 17:42:01
re: 2nd proof w/ a cheatAmon2005-05-05 00:36:33
Some Thoughts2nd proof w/ a cheatnikki2005-05-04 19:54:38
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