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Squaring sides (Posted on 2005-05-04) Difficulty: 4 of 5
Take any convex quadrilateral ABCD, with diagonals AC and BD. Pick E so ABCE is a parallelogram. Prove that AB²+BC²+CD²+DA²= AC²+BD²+DE².

Given the same quadrilateral, let P and Q be the midpoints of AC and BD. Now prove that AB²+BC²+CD²+DA²= AC²+BD²+4PQ².

See The Solution Submitted by Federico Kereki    
Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: 2nd proof w/ a cheat | Comment 2 of 4 |
(In reply to 2nd proof w/ a cheat by nikki)

hahah ^^nice job nikki~ =)

i'm working on the first proof...soo rusty on this kinda math...=_=
  Posted by Amon on 2005-05-05 00:36:33

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