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Any order will do (Posted on 2005-07-12) Difficulty: 3 of 5
The numbers from 1 to 2n are separated into two lists of n numbers each, A and B; elements are ordered so a1<a2<...<an and b1>b2>...>bn.

How much is |a1-b1|+|a2-b2|+...+|an-bn|?

See The Solution Submitted by Federico Kereki    
Rating: 3.6667 (3 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
answerK Sengupta2010-05-29 04:10:32
re: Proof (spoiler)Richard2005-07-13 02:18:32
SolutionProof (spoiler)Tristan2005-07-12 23:05:07
re(2): thoughts -HTML issuesJosh706792005-07-12 17:57:07
Solutionre: thoughts -oops (spoiler)Josh706792005-07-12 17:35:37
Some ThoughtsBy inspection... no proof !pcbouhid2005-07-12 17:24:15
re: thoughtsRichard2005-07-12 17:15:22
Some ThoughtsthoughtsJosh706792005-07-12 16:51:52
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