All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > General
Dinner and Dialogue (Posted on 2005-11-02) Difficulty: 4 of 5
The Dinner and Dialogue Club has planned a series of small meetings. Each meeting would consist of two or three members enjoying friendly conversation with each other while eating food from different places all over the world. Each member is scheduled to meet exactly four times. No pair of members will meet twice, but some pairs might not meet at all.

The first thing the club did was schedule and arrange the meetings so that each member knew whom to meet and when. When it came to choosing restaurants, someone suggested that each member eat at two restaurants with eastern food, and two with western food (each restaurant is either one or the other). They liked the idea, but to their dismay, the idea was not possible without rearranging at least some of the meetings.

What possible meeting schedule might cause this to happen? How many members are there in this club, at the least?

See The Solution Submitted by Tristan    
Rating: 3.6667 (3 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(2): Least number of members ?Penny2005-11-08 03:22:27
re: Least number of members ?Tristan2005-11-07 19:19:54
Least number of members ?Penny2005-11-05 16:28:37
SolutionSolution for the Conversing Club (computer program used)Penny2005-11-05 16:05:44
More First ThoughtsgoFish2005-11-05 02:08:19
re: SolutionTristan2005-11-05 01:36:54
SolutionJeramie2005-11-04 21:14:09
First thoughtsgoFish2005-11-04 06:38:31
Hints/TipsNo SubjectTristan2005-11-03 17:47:50
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information