perplexus.info :: Probability : Trading cards

Trading cards (Posted on 2002-05-03)

A trading card series has 200 different cards in it, which are sold in 5-card packages.

Each package has a random sampling of the cards (assume that any card of the 200 has an equal chance of being in a package).

On the average, how many packages will need to be bought to collect the complete series if...

A: all the cards in a package will always be different

B: a package can have repeats

See The Solution Submitted by levik

Rating: 4.1818 (11 votes)

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Trading online	TobyGates	2022-11-24 01:23:38
Puzzle Answer	K Sengupta	2022-09-19 04:17:38
Trading cards	Whia1967	2022-09-19 04:02:22
hmm	Joe C	2003-11-05 14:13:39
my methods and Charlie's corrections	Steve Hutton	2003-03-09 02:07:57
re(2): a method of solving problem A	Charlie	2003-02-06 09:07:50
re: a method of solving problem A	Charlie	2003-02-06 09:01:32
re: Another analytic solution to problem B	Charlie	2003-02-06 05:55:44
Another analytic solution to problem B	Rick	2003-02-05 12:06:52
re(2): a method of solving problem B	Charlie	2003-02-05 08:57:29
re: a method of solving problem B	Charlie	2003-02-05 08:53:56
re(2): Analytic solution, A and B missing parens added	Charlie	2003-02-05 08:36:48
re: Analytic solution, A and B missing parens added	Charlie	2003-01-31 09:17:10
Analytic solution, A and B	Charlie	2003-01-31 08:33:22
Analytic Solution to Part B(ctd.--part 3)	Charlie	2003-01-30 10:01:13
Analytic Solution to Part B (ctd.)	Charlie	2003-01-30 09:59:15
Analytic Solution to Part B	Charlie	2003-01-30 09:56:57
re(3): Simulation results	Charlie	2003-01-29 17:01:55
re(3): Simulation results	Charlie	2003-01-29 17:00:45
re(2): Simulation results	Tony	2003-01-29 13:25:16
re: Simulation results	Charlie	2003-01-29 10:15:58
Simulation results	Tony	2003-01-24 13:39:11
cards	terry	2003-01-19 19:17:29
trading cards	terry	2002-12-25 06:51:56
re: Trading cards	terry	2002-12-20 02:47:19
Trading cards	terry	2002-12-19 21:18:36
re: This should be the answer	Cory Taylor	2002-11-29 08:58:07
This should be the answer	Sophia	2002-11-29 03:19:56
attempt at case B	Keedom	2002-11-19 00:26:36
attempt ar case A	Keedom	2002-11-18 23:59:16
a method of solving problem A	Steve Hutton	2002-07-31 13:55:51
a method of solving problem B	Steve Hutton	2002-07-31 13:51:49
re: my result	Steve Hutton	2002-07-28 06:05:44
my result	Cheradenine	2002-06-11 08:22:50
No Subject	Cheradenine	2002-06-11 08:21:18
re: it's more complicated	levik	2002-05-26 12:27:41
My thoughts	TomM	2002-05-10 08:32:37
its more complicated	Eamon	2002-05-10 00:01:49
Possible solution	Half-Mad	2002-05-07 23:33:12

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