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Trading cards (Posted on 2002-05-03) Difficulty: 3 of 5
A trading card series has 200 different cards in it, which are sold in 5-card packages.

Each package has a random sampling of the cards (assume that any card of the 200 has an equal chance of being in a package).

On the average, how many packages will need to be bought to collect the complete series if...

  • A: all the cards in a package will always be different
  • B: a package can have repeats

  • See The Solution Submitted by levik    
    Rating: 4.1818 (11 votes)

    Comments: ( You must be logged in to post comments.)
      Subject Author Date
    Some ThoughtshmmJoe C2003-11-05 14:13:39
    my methods and Charlie's correctionsSteve Hutton2003-03-09 02:07:57
    re(2): a method of solving problem ACharlie2003-02-06 09:07:50
    Solutionre: a method of solving problem ACharlie2003-02-06 09:01:32
    Hints/Tipsre: Another analytic solution to problem BCharlie2003-02-06 05:55:44
    SolutionAnother analytic solution to problem BRick2003-02-05 12:06:52
    re(2): a method of solving problem BCharlie2003-02-05 08:57:29
    Hints/Tipsre: a method of solving problem BCharlie2003-02-05 08:53:56
    re(2): Analytic solution, A and B missing parens addedCharlie2003-02-05 08:36:48
    re: Analytic solution, A and B missing parens addedCharlie2003-01-31 09:17:10
    SolutionAnalytic solution, A and BCharlie2003-01-31 08:33:22
    Analytic Solution to Part B(ctd.--part 3)Charlie2003-01-30 10:01:13
    Analytic Solution to Part B (ctd.)Charlie2003-01-30 09:59:15
    Analytic Solution to Part BCharlie2003-01-30 09:56:57
    re(3): Simulation resultsCharlie2003-01-29 17:01:55
    re(3): Simulation resultsCharlie2003-01-29 17:00:45
    re(2): Simulation resultsTony2003-01-29 13:25:16
    re: Simulation resultsCharlie2003-01-29 10:15:58
    Some ThoughtsSimulation resultsTony2003-01-24 13:39:11
    cardsterry2003-01-19 19:17:29
    trading cardsterry2002-12-25 06:51:56
    re: Trading cardsterry2002-12-20 02:47:19
    SolutionTrading cardsterry2002-12-19 21:18:36
    re: This should be the answerCory Taylor2002-11-29 08:58:07
    This should be the answerSophia2002-11-29 03:19:56
    Some Thoughtsattempt at case BKeedom2002-11-19 00:26:36
    Some Thoughtsattempt ar case AKeedom2002-11-18 23:59:16
    a method of solving problem ASteve Hutton2002-07-31 13:55:51
    a method of solving problem BSteve Hutton2002-07-31 13:51:49
    re: my resultSteve Hutton2002-07-28 06:05:44
    my resultCheradenine2002-06-11 08:22:50
    No SubjectCheradenine2002-06-11 08:21:18
    re: it's more complicatedlevik2002-05-26 12:27:41
    My thoughtsTomM2002-05-10 08:32:37
    its more complicatedEamon2002-05-10 00:01:49
    Possible solutionHalf-Mad2002-05-07 23:33:12
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