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A trading card series has 200 different cards in it, which are sold in 5-card packages.

Each package has a random sampling of the cards (assume that any card of the 200 has an equal chance of being in a package).

On the average, how many packages will need to be bought to collect the complete series if...

• A: all the cards in a package will always be different
• B: a package can have repeats

•  See The Solution Submitted by levik Rating: 4.1818 (11 votes)

 Subject Author Date hmm Joe C 2003-11-05 14:13:39 my methods and Charlie's corrections Steve Hutton 2003-03-09 02:07:57 re(2): a method of solving problem A Charlie 2003-02-06 09:07:50 re: a method of solving problem A Charlie 2003-02-06 09:01:32 re: Another analytic solution to problem B Charlie 2003-02-06 05:55:44 Another analytic solution to problem B Rick 2003-02-05 12:06:52 re(2): a method of solving problem B Charlie 2003-02-05 08:57:29 re: a method of solving problem B Charlie 2003-02-05 08:53:56 re(2): Analytic solution, A and B missing parens added Charlie 2003-02-05 08:36:48 re: Analytic solution, A and B missing parens added Charlie 2003-01-31 09:17:10 Analytic solution, A and B Charlie 2003-01-31 08:33:22 Analytic Solution to Part B(ctd.--part 3) Charlie 2003-01-30 10:01:13 Analytic Solution to Part B (ctd.) Charlie 2003-01-30 09:59:15 Analytic Solution to Part B Charlie 2003-01-30 09:56:57 re(3): Simulation results Charlie 2003-01-29 17:01:55 re(3): Simulation results Charlie 2003-01-29 17:00:45 re(2): Simulation results Tony 2003-01-29 13:25:16 re: Simulation results Charlie 2003-01-29 10:15:58 Simulation results Tony 2003-01-24 13:39:11 cards terry 2003-01-19 19:17:29 trading cards terry 2002-12-25 06:51:56 re: Trading cards terry 2002-12-20 02:47:19 Trading cards terry 2002-12-19 21:18:36 re: This should be the answer Cory Taylor 2002-11-29 08:58:07 This should be the answer Sophia 2002-11-29 03:19:56 attempt at case B Keedom 2002-11-19 00:26:36 attempt ar case A Keedom 2002-11-18 23:59:16 a method of solving problem A Steve Hutton 2002-07-31 13:55:51 a method of solving problem B Steve Hutton 2002-07-31 13:51:49 re: my result Steve Hutton 2002-07-28 06:05:44 my result Cheradenine 2002-06-11 08:22:50 No Subject Cheradenine 2002-06-11 08:21:18 re: it's more complicated levik 2002-05-26 12:27:41 My thoughts TomM 2002-05-10 08:32:37 its more complicated Eamon 2002-05-10 00:01:49 Possible solution Half-Mad 2002-05-07 23:33:12

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