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Trading cards (Posted on 2002-05-03) Difficulty: 3 of 5
A trading card series has 200 different cards in it, which are sold in 5-card packages.

Each package has a random sampling of the cards (assume that any card of the 200 has an equal chance of being in a package).

On the average, how many packages will need to be bought to collect the complete series if...

  • A: all the cards in a package will always be different
  • B: a package can have repeats

  •   Submitted by levik    
    Rating: 4.1818 (11 votes)
    Solution: (Hide)
    After a long tenure on the "Unsolved" list, there have been some users who posted solutions agreeing with one another in their results.

    Please refer to the comments on this problem to read them.

    Comments: ( You must be logged in to post comments.)
      Subject Author Date
    Some ThoughtshmmJoe C2003-11-05 14:13:39
    my methods and Charlie's correctionsSteve Hutton2003-03-09 02:07:57
    re(2): a method of solving problem ACharlie2003-02-06 09:07:50
    Solutionre: a method of solving problem ACharlie2003-02-06 09:01:32
    Hints/Tipsre: Another analytic solution to problem BCharlie2003-02-06 05:55:44
    SolutionAnother analytic solution to problem BRick2003-02-05 12:06:52
    re(2): a method of solving problem BCharlie2003-02-05 08:57:29
    Hints/Tipsre: a method of solving problem BCharlie2003-02-05 08:53:56
    re(2): Analytic solution, A and B missing parens addedCharlie2003-02-05 08:36:48
    re: Analytic solution, A and B missing parens addedCharlie2003-01-31 09:17:10
    SolutionAnalytic solution, A and BCharlie2003-01-31 08:33:22
    Analytic Solution to Part B(ctd.--part 3)Charlie2003-01-30 10:01:13
    Analytic Solution to Part B (ctd.)Charlie2003-01-30 09:59:15
    Analytic Solution to Part BCharlie2003-01-30 09:56:57
    re(3): Simulation resultsCharlie2003-01-29 17:01:55
    re(3): Simulation resultsCharlie2003-01-29 17:00:45
    re(2): Simulation resultsTony2003-01-29 13:25:16
    re: Simulation resultsCharlie2003-01-29 10:15:58
    Some ThoughtsSimulation resultsTony2003-01-24 13:39:11
    cardsterry2003-01-19 19:17:29
    trading cardsterry2002-12-25 06:51:56
    re: Trading cardsterry2002-12-20 02:47:19
    SolutionTrading cardsterry2002-12-19 21:18:36
    re: This should be the answerCory Taylor2002-11-29 08:58:07
    This should be the answerSophia2002-11-29 03:19:56
    Some Thoughtsattempt at case BKeedom2002-11-19 00:26:36
    Some Thoughtsattempt ar case AKeedom2002-11-18 23:59:16
    a method of solving problem ASteve Hutton2002-07-31 13:55:51
    a method of solving problem BSteve Hutton2002-07-31 13:51:49
    re: my resultSteve Hutton2002-07-28 06:05:44
    my resultCheradenine2002-06-11 08:22:50
    No SubjectCheradenine2002-06-11 08:21:18
    re: it's more complicatedlevik2002-05-26 12:27:41
    My thoughtsTomM2002-05-10 08:32:37
    its more complicatedEamon2002-05-10 00:01:49
    Possible solutionHalf-Mad2002-05-07 23:33:12
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