Number the corners of a cube from 1 to 8, so that the sum of the four corners of every face is the same.
Let the denote the six faces of the given cube as follows:
Top Face: ABCD
Bottom Face: EFGH
Left Side Face: AEHD
Right Side Face: BFGC
Front Face : DCGH
Back Face: ABFE
Then the numbers to be placed on each of its eight vertices A, B, C, D, E, F, G and H in conformity with the provisions of the given problem are as follows:
A = 1; B= 4; C =7; D = 6; E = 8; F = 5; G = 2; H= 3
Edited on June 29, 2007, 11:48 pm
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