All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Magic Cubic (Posted on 2005-11-28) Difficulty: 2 of 5
Number the corners of a cube from 1 to 8, so that the sum of the four corners of every face is the same.

No Solution Yet Submitted by sragen    
Rating: 2.6667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Puzzle Resolution | Comment 10 of 14 |

Let the denote the six faces of the given cube as follows:

Top Face: ABCD

Bottom Face: EFGH

Left Side Face: AEHD

Right Side Face: BFGC

Front Face :  DCGH

Back Face: ABFE

Then the numbers to be placed on each of its eight vertices A, B, C, D, E, F, G and H in conformity with the provisions of the given problem are as follows:

A = 1; B= 4; C =7; D = 6; E = 8; F = 5; G = 2; H= 3

Edited on June 29, 2007, 11:48 pm
  Posted by K Sengupta on 2007-06-29 23:47:25

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information