Number the corners of a cube from 1 to 8, so that the sum of the four corners of every face is the same.

Let the denote the six faces of the given cube as follows:

Top Face: ABCD

Bottom Face: EFGH

Left Side Face: AEHD

Right Side Face: BFGC

Front Face : DCGH

Back Face: ABFE

Then the numbers to be placed on each of its eight vertices A, B, C, D, E, F, G and H in conformity with the provisions of the given problem are as follows:

A = 1; B= 4; C =7; D = 6; E = 8; F = 5; G = 2; H= 3

*Edited on ***June 29, 2007, 11:48 pm**