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How Many Pairs (Posted on 2006-03-14) Difficulty: 2 of 5
The sum of two positive numbers is 1068 and their Highest Common Factor is 89. How many pairs of such numbers are there?

No Solution Yet Submitted by Ravi Raja    
Rating: 2.5000 (6 votes)

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modification to bobz solution | Comment 2 of 13 |
bob...if you see your soln. , u will find that (2,10) cannot be the solun.. becaz in that case no. are 2*89 and 10*89 which has a HCF of 2*89 . similar case with other solutions where x and y are not mutually prime! hence we are left with only 2 case ...(1,11) and (5,7) .

hence 2 such pairs possible ....


  Posted by avijit on 2006-03-14 08:08:10
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