The sum of two positive numbers is 1068 and their Highest Common Factor is 89. How many pairs of such numbers are there?
bob...if you see your soln. , u will find that (2,10) cannot be the
solun.. becaz in that case no. are 2*89 and 10*89 which has a HCF of
2*89 . similar case with other solutions where x and y are not mutually
prime! hence we are left with only 2 case ...(1,11) and (5,7) .
hence 2 such pairs possible ....
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Posted by avijit
on 2006-03-14 08:08:10 |
modification to bobz solution
