Which is the number that, multiplied by 3, then increased by three-fourths of the product, divided by 7, diminished by one-third of the quotient, multiplied by itself, diminished by 52, the square root found, addition of 8, division by 10, gives the number 2 ?
(In reply to
answer by K Sengupta)
Let the number obtained at the final operation be S(1), the number obtained at the penultimate operation be S (2) , and..., so on.
Then, by conditions of the given problem, we must have:
S(1) =2=> S(2)/10=2=> S(2)=20
S(2)=S(3)+8=20=> S(3)= 12
S(3) =vS(4) => S(4)=12^2=144
S(4)=S(5)-52=> S(5)=144+52=196
S(5)=(S(6))^2=> S(6) = v(196) = +/-14
S(6)=(2/3)*S(7) => S(7) =(3/2)*(+/-14) = +/-21
S(7)= S(8)/7 => S(8) = 7*(+/-21) = +/-147
S(8)= (7/4)*S(9)=> S(9)= (4/7)*S(8) =(4/7)*(+/-147)= +/-84
S(9)=3*S(10)=> S(10)=S(9)/3 = (+/-84)/3 = +/-28
Consequently, the required number is 28 or, -28.
Edited on January 1, 2022, 12:27 am
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