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3 age problems (Posted on 2006-03-24) Difficulty: 3 of 5
I A domestic partnership of two consenting adults has three children, Alice, Bob, and Charlie, and the difference between the adults' ages was the same as between Alice and Bob and between Bob and Charlie. The product of Alice and Bob’s ages equaled one parent's age. The product of Bob and Charlie’s ages equaled the other parent's age. The sum of the five ages amounted to ninety years. What was the age of each person?

II A woman has nine children(!), all born at regular intervals, and the sum of the squares of their ages (in years) was equal to the square of her own. What was the age of each child?

III Boadicea died one hundred and twenty-nine years after Cleopatra was born. Their combined life-span was one hundred years. Cleopatra died in 30 B.C.E. When was Boadicea born?

See The Solution Submitted by Jer    
Rating: 3.0000 (2 votes)

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Solution Solution Parts I and III | Comment 2 of 5 |

Part I: The parents are both 36 years old.  The children are triplets, each 6 years old.  If you write formulas for their ages, this is the only possible solution.

Part III: Boadicea was born in 1 BCE(?).  I'm probably missing some trick with the years when it switches over, so my official answer is that Boadicea was born 29 years after Cleopatra died, however you want to count the years.


  Posted by tomarken on 2006-03-24 08:18:08
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