On a working escalator, one man walking down it took 50 steps. Another man, walking three times faster, took 75 steps.
How many steps would each man take going down the same escalator during a power outage?
Let the total number of steps in the excalator be x.
Then, by the problem the slower man will cover (x-50) steps in
precisely thrice the time it will take the faster man to take x-75 steps.
Thus, (x-50) = 3(x-75), giving: x = 87.5
Hence each man must take precisely 87.5 steps during a power outage.
Edited on April 25, 2007, 1:54 am