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 Remainder (Posted on 2003-03-01)
Show that the remainder when 2^1990 (2 to the power of 1990) is divided by 1990 equals 1024.

 See The Solution Submitted by Anoop Rating: 3.8750 (8 votes)

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 Step by Step | Comment 5 of 12 |
As modular arithmetic allows that taking a power can be accomplished one step at a time, multiplying my the number whose power is taken and reducing by the modulus, as many times as needed per the definition of a power, we can raise 1024 (which is 2^10) to the 199 power mod 1990 one step at a time:
1024^2 mod 1990 = 1836. Then 1836 * 1024 mod 1990 = 1504, which is therefore 1024^3 mod 1990. Continue that process another 196 times to get 1024^199 mod 1990, which is 2^1990 mod 1990.
 Posted by Charlie on 2003-03-02 09:32:32

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