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Simple distances (Posted on 2006-05-01) Difficulty: 3 of 5
For this you will need four pennies. Arrange the pennies so that the centers of all four are equidistant from each other.


(1) (2) (3) (4)

This will not work because penny 1 and penny 4 are farther apart than penny 1 and penny 2.

See The Solution Submitted by Stephen    
Rating: 1.8571 (7 votes)

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hint | Comment 1 of 8

three- is easy,  2r distance!

the fourth not in the same plane

  Posted by Ady TZIDON on 2006-05-01 09:17:37
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