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Simple distances (Posted on 2006-05-01) Difficulty: 3 of 5
For this you will need four pennies. Arrange the pennies so that the centers of all four are equidistant from each other.

Example:

(1) (2) (3) (4)

This will not work because penny 1 and penny 4 are farther apart than penny 1 and penny 2.

See The Solution Submitted by Stephen    
Rating: 1.8571 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
hint | Comment 1 of 8

three- is easy,  2r distance!

the fourth not in the same plane


  Posted by Ady TZIDON on 2006-05-01 09:17:37
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