For this you will need four pennies. Arrange the pennies so that the centers of all four are equidistant from each other.
(1) (2) (3) (4)
This will not work because penny 1 and penny 4 are farther apart than penny 1 and penny 2.
(In reply to Maybe a Solution
Good guess... but I wasn't calling for "Horizontal distance," simply distance. So in your case the bottom and top pennies would be farther away from eachother than the top two.
Posted by Stephen
on 2006-05-13 14:13:32