(In reply to
Willing to bet by e.g.)
Indeed, by taking the base2 log of each side we get
x = 2^65520 * log2(x)
and then doing the same again
log2(x) = 65520 + log2(log2(x))
If x=2^(2^16), then log2(x) = 2^16 = 65536 and log2(log2(x)) = 16, and the equation is satisfied, so
log2(log2(x)) = 16
Sweet.

Posted by Charlie
on 20060611 11:36:08 