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A Multi-solution Puzzle (Posted on 2006-08-03) Difficulty: 3 of 5
Consider the equation:

(3P2Q) = 24PQ/(3P+2Q-1)

where P and Q are positive integers. It can be verified that (P=5, Q=5) and (P=26, Q=33) are two solutions.

(A) Can you give at least three other solutions to the above equation?

(B) Determine whether or not the equation admits of an infinite number of solutions.

See The Solution Submitted by K Sengupta    
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  Subject Author Date
re: what mathematica has to sayRichard2006-08-03 19:14:50
what mathematica has to sayDaniel2006-08-03 18:03:12
Some answers w/o derivationsRichard2006-08-03 16:41:51
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