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 Are all complex numbers real? (Posted on 2006-08-24)
Let's "prove" that every complex number z is real.

If z=0 it's obvious. For all other complex numbers z=r*e^(θi), where r is a real number, and i=√-1.

Now, z= r*e^(θi)= r*(e^(2πi))^(θ/2π). Now as we know that e^(2πi)=1 we can write z =r*(1)^(θ/2π) → z=r.

What's wrong with this?

 No Solution Yet Submitted by atheron Rating: 3.3333 (3 votes)

 Subject Author Date a possible solution zohaib ahmed 2007-03-05 11:57:52 a possible solution zohaib ahmed 2007-03-05 11:57:32 Solution Danny 2007-01-06 22:29:02 No Subject popa 2006-10-13 10:47:26 possible solution vivek 2006-09-22 14:15:10 re(3): The Specific Problem (fleshed out a bit more) JLo 2006-08-28 09:59:09 re(2): The Specific Problem (fleshed out a bit more) Richard 2006-08-27 17:42:25 re(2): The Specific Problem (fleshed out a bit more) Richard 2006-08-26 22:45:33 re: The Specific Problem (fleshed out a bit more) JLo 2006-08-26 19:11:51 The Specific Problem Richard 2006-08-25 22:33:15 I think this is wrong because... JLo 2006-08-24 19:24:54 re(2): The General Problem Richard 2006-08-24 17:32:19 re: The General Problem Federico Kereki 2006-08-24 16:27:36 The General Problem Richard 2006-08-24 15:54:55

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