All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Generation Gap (Posted on 2003-04-25)
The following relationships hold among the ages of the members of a family of four. (All ages are integral).

(a) The mother is three times as old as the daughter was when the father was the same age as the mother is now.

(b) When the daughter reaches half the age the mother is now, the son will be half as old as the father was when the mother was twice the age the daughter is now.

(c) When the father reaches twice the age the mother was when the daughter was the same age as the son is now, the daughter will be four times as old as the son is now.

Given that one of their ages is a perfect square, what are the four ages ?

 See The Solution Submitted by Ravi Raja Rating: 3.8333 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re: solution -- Correction | Comment 2 of 5 |
(In reply to solution by Charlie)

Where I said

"in M/2 - D years, at which time the son will be S + M/2 + D, so

S + M/2 + D = (F-(M-2D))/2"

the S + M/2 + D should of course be S + M/2 - D.

The equations which followed from this are correct as the mistake was in typing in what I had on paper.
 Posted by Charlie on 2003-04-25 04:34:46

 Search: Search body:
Forums (0)