perplexus.info :: Sequences : Twist in Sequence

Twist in Sequence (Posted on 2006-11-16)


            | 59
+---+---+---+---
|   |   |   | 94
+---+---+---+---
|   |   |   | 81
+---+---+---+---
|   |   |   |110
+---+---+---+---
|194| 41| 50|107

The numbers are the totals of the rows, columns and diagonals
of a 'magic square'.

Describe the common sequence which they hide.

See The Solution Submitted by brianjn

Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: uniqueness of the numbers

| Comment 3 of 10 |

(In reply to uniqueness of the numbers by Larry)

The center square can only be 1. If you label the squares left-to-right, top-to-bottom, A through J (omitting I), then:

A = 107 - E - J
B = 41 - E -H
C = 59 - E - G

A + B + C = 94
207 - 3E - G - H - J = 94
207 - 3E - 110 = 94
3E = 3
E = 1

I brute forced the rest of it, so there very well might be other integer solutions that work.

Posted by Jyqm on 2006-11-16 12:31:01

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