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A Factorial Triplet Puzzle (Posted on 2007-01-31) Difficulty: 3 of 5
Determine all possible triplets of integers (n,m,k) satisfying 1!+2!+3!+...+n!=mk, where n, m and k are greater than 1.

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

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re(2): some thoughts -- n from 1 to n Comment 5 of 5 |
(In reply to re: some thoughts by Dej Mar)

Although that is a logical interpretation, it is common on here (where summation notation is too awkward) to simply spell out the relationship, thus adding up each term. If n=1, we would simply see 1!

If K had simply wrote 1!+...+n!, it would be unclear what terms she wanted added, and if she wanted to include 1!, she would have had to write just 1!... or ...+n!


  Posted by Gamer on 2007-02-02 01:09:20
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