I'm looking for a 4 digit square number where its first two digits are a square as are the last two.

What is its square root?

Incidentally, I'm not interested in the square of zero.

The following is a solution in Python (a free programming language, ideal for these kinds of problems, and many others).

from math import sqrt
for n in [i*i for i in range(1+int(sqrt(1000)),int(sqrt(10000)))]:
   if int(sqrt(n/100)) == sqrt(n/100) != 0  and int(sqrt(n%100)) == sqrt(n%100) != 0:
      print sqrt(n)

Posted by Ken Haley on 2007-05-05 00:29:47