All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > General
Magic trick (Posted on 2007-05-11) Difficulty: 3 of 5
Two magicians A and B perform the following trick:

A leaves the room and B chooses 4 members from the audience at random. Each member chooses a card numbered from 1 to 100 (each chooses a different card) and after B has seen their cards he chooses a card from the remaining deck of cards. The 5 chosen cards are shuffled by an audience member and handed to A who just returned to the room. Prove that A is able to figure out which cards each member picked. Consider that the chosen members form a row and e.g. the leftmost member picks the first card and the rightmost member (B) picks the last card.

No Solution Yet Submitted by atheron    
Rating: 4.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Non-math solution (if this was in Tricks) | Comment 38 of 51 |

1. A and B are the same magician, although the audience believes they are two different magicians.  Not too difficult a trick for a good magician to perform.

2. A leaves the room and a half-second later B enters the room (but looks quite different from A).

3. B chooses 4 members from the audience at random, who each choose a different card.

4. B then picks his card.

5. An audience member then shuffles the cards.

6. This is when B leaves the room and a half-second later A returns to the room looking like he did before.

7. The audience member hands the shuffled cards to A, who already knows which member picked which card since he is also B.

  Posted by Guest on 2007-05-15 19:47:28
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information