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# Wrong = % Right (Posted on 2007-06-16) Difficulty: 2 of 5
I finished grading tests for two classes when I noticed something interesting about the worst scoring student for each.

In the first class a student who got 46 problems wrong got 46 percent right (to the nearest whole percent.)
How many problems were there on this test?

In the second class there were 35 problems but again the lowest scoring student got the same number wrong as percent right (again rounded.)
How many questions did this student get wrong?

What is the smallest number of questions for which this kind of thing can happen?
(Aside from the trivial one question test.)

What if the percent must be exact instead of rounded?

[Note: This actually happened.]

See The Solution Submitted by Jer    
Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution To The Third Part : Exact Case Comment 6 of 6 |
(In reply to Solution To The Third Part : Approximate Case by K Sengupta)

Let the respective exact total number of questions and the questions responded to incorrectly be P and Q.

Then, by the problem:

(i) P< Q
(ii) P - Q = 100*(Q/P)

from (ii), we obtain:
= P^2/(100+P)
= (P-100) +  10000/(100+P)

Thus, (100+P) must divide 10000. The minimum value of P for which this is posible occurs at P = 25, giving: Q = 625/125 = 5.

Consequently , the smallest total number of questions for which this can happen is 25 (with the number of questions answered incorrectly being 5).

Edited on October 18, 2007, 12:52 pm
  Posted by K Sengupta on 2007-06-17 05:27:04

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