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A system of modular equations (Posted on 2008-07-20) Difficulty: 3 of 5
Solve the following set of equations for positive integers a and b:

1919(a)(b) mod 5107 = 1
1919(a+1)(b-1) mod 5108 = 5047
1919(a+2)(b-2) mod 5109 = 1148
1919(a+3)(b-3) mod 5110 = 3631
1919(a+4)(b-4) mod 5111 = 2280

See The Solution Submitted by pcbouhid    
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  Subject Author Date
re(7): Solution ------ can you check?K Sengupta2008-08-05 11:57:01
re(6): Solution ------ can you check?pcbouhid2008-08-04 09:11:30
re(5): Solution ------ can you check?K Sengupta2008-08-02 13:07:24
re(4): Solution ------ can you check?K Sengupta2008-08-01 13:28:02
re(3): Solution ------ can you check?pcbouhid2008-08-01 13:05:37
re(2): Solution ------ can you check?K Sengupta2008-08-01 06:32:41
re: Solution ------ can you check?pcbouhid2008-07-31 17:12:43
SolutionSolutionK Sengupta2008-07-20 14:26:13
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