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No. of Distinct Solutions(1) (Posted on 2008-07-05) Difficulty: 3 of 5
Given that a and b are non-negative integers and f(x,y)=(x+y-a)(x+y-b), then if f(x,y)=0 has n distinct non-negative integer solutions for (x,y), find how many different polynomials f(x,y) can take.

Note: For example, (1,0) and (0,1) are not distinct solutions.

No Solution Yet Submitted by Praneeth    
Rating: 3.5000 (2 votes)

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  Subject Author Date
Puzzle Thoughts K Sengupta2023-08-09 04:42:40
SolutionJust counting (spoiler)Steve Herman2008-07-06 01:35:12
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