All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
No. of Distinct Solutions(1) (Posted on 2008-07-05) Difficulty: 3 of 5
Given that a and b are non-negative integers and f(x,y)=(x+y-a)(x+y-b), then if f(x,y)=0 has n distinct non-negative integer solutions for (x,y), find how many different polynomials f(x,y) can take.

Note: For example, (1,0) and (0,1) are not distinct solutions.

No Solution Yet Submitted by Praneeth    
Rating: 3.5000 (2 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionJust counting (spoiler)Steve Herman2008-07-06 01:35:12
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information