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ABC's Of Greatest Divisor (Posted on 2008-09-18) Difficulty: 2 of 5
The greatest common divisor of three positive integers 90ABC17, 79ABC and 491ABC4 is ≥ 2, where each of A, B and C represents a different base 10 digit from 0 to 9.

Determine all possible triplet(s) (A,B,C) that satisfy the given conditions.

Note: While a solution is trivial with the aid of a computer program, show how to derive it without one.

See The Solution Submitted by K Sengupta    
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  Subject Author Date
SolutionsolutionDej Mar2008-09-19 00:53:30
Remembered!! Im still in the game?pcbouhid2008-09-18 15:56:33
No merit in cheating...pcbouhid2008-09-18 13:39:04
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