I have cows, horses and dogs, a different prime number of each. If I multiply the number of cows (c) by the total of cows and horses (c+h), the product is 120 more than the number of dogs (d), that is: c*(c+h) = 120 + d.

How many of each do I have?

(In reply to Agreed by ed bottemiller)

Whew!  I feel better.  I too kind of got lured by 'the prime pair difference of 2' thing, and looked, for example, at 17/19, 29/31 to check it out.  Anyway, you've got the solution nailed, unless Charlie, using routines far beyond my comprehension, gets anything different.

Posted by rod hines on 2008-10-20 17:18:19