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Digital power (Posted on 2008-11-15) Difficulty: 2 of 5
Find all numbers N = a1a2a3...an greater than 1, with no leading zeros, no zeros, which fits this equation:

N = a1a1 + a2a2 + a3a3 + ... + anan

Clarifying, N = 23 doesn´t work because 22 + 33 is equal to 31, not 23.

See The Solution Submitted by pcbouhid    
Rating: 5.0000 (1 votes)

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Some Thoughts re:2nd Solution : Zero to the zero power | Comment 3 of 6 |
(In reply to Second Computer Solution by brianjn)

 

If you research the definition of 0^0 you will find  that it should be set according to the needs of a specific problem.

Depending on the context where 0^0 occurs, you might wish to substitute it with 1, indeterminate or undefined/nonexistent 

One might say that  a^0 is 1 for any a , the other will claim that  0^a is zero for any a ,      but  if we  consider functions f(x) and g(x) then the limit of f^g when x ==>0 may be any number between 0 and 1; e.g. lim (e^(-1/x))^x equals 1/e if x ==>0.

Since our problem specifies "no zeros" I see no reason  to introduce an irrelevant definition of 0^0=0.

Please try Google (several entries) for
Zero to the zero power


  Posted by Ady TZIDON on 2008-11-15 23:37:51
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