All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Fifth root (cubic) = Cube root (quintic) (Posted on 2009-04-05) Difficulty: 3 of 5
Find all possible real number(s) N that satisfy this equation:

5√(N3 + 2N) = 3√(N5 - 2N)

where, the common value of both sides of the equation is positive.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Oops! Solution by reading the problem. | Comment 3 of 5 |
(In reply to Oops! Solution by reading the problem. by Steve Herman)

actually it has several imaginary solutions a couple simple ones are N=+-i.

Using a computer algebra system there are 3 real and 20 complex solutions with N=0 having multiplicity of 3.  Which makes sense because when the equation is expanded you end up with a 25 degree polynomial.

  Posted by Daniel on 2009-04-05 17:54:38
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (44)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information