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 Sequence with only 3 numbers (Posted on 2009-03-07)
Trying to define a way to generate the terms of a sequence, and starting with the number 5, I found, surprisingly, that the way I used generated this sequence:

5, 8, 11, 5, 8, 11, 5, 8, 11, ...

And these 3 numbers repeat in this order indefinitely.

Define a simple way to generate this sequence.

 Submitted by pcbouhid Rating: 2.0000 (1 votes) Solution: (Hide) My simple way was: square the previous one, add the digits, plus 1.Watch this:2, 5, 8, 11,...3, 10, 2, 5, 8, 11,...4, 8, 11, 5, 8, 11,...6, 10, 2, 5, 8, 11,...7, 14, 17, 20, 5, 8, 11,...22, 17, 20, 5, 8, 11,...etc...That is, no matter the "seed", I always get the periodic 5, 8, 11!!!!!This can be proved? I didnīt find (yet) a counterproof!!

 Subject Author Date re: to the question posed in the official solution (spoiler) pcbouhid 2009-03-11 18:11:41 to the question posed in the official solution (spoiler) Charlie 2009-03-11 10:55:45 Another simple way... Dej Mar 2009-03-10 10:44:37 My solution Robby Goetschalckx 2009-03-10 05:24:31 re(2): How to solve it recursively? 10 excess Gamer 2009-03-10 02:03:31 re: How to solve it recursively? 10 excess Ady TZIDON 2009-03-09 08:19:31 How to solve it recursively? Gamer 2009-03-08 00:36:18 general solution Daniel 2009-03-07 22:59:00 Recurrence Harry 2009-03-07 19:22:16 WITHOUT MOD Ady TZIDON 2009-03-07 16:50:19 my solution Daniel 2009-03-07 14:09:34

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