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A! + B! + C! = 3D (Posted on 2009-08-27) Difficulty: 2 of 5
Determine all possible quadruplet(s) (A, B, C, D) of nonnegative integer(s), with A < B < C, that satisfy this equation:

A! + B! + C! = 3D

See The Solution Submitted by K Sengupta    
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  Subject Author Date
re: Metaphysics?Charlie2009-08-29 00:41:21
Metaphysics?ed bottemiller2009-08-28 21:02:36
SolutionSolutionDej Mar2009-08-28 11:18:06
Spreadsheet & Computer without proofbrianjn2009-08-27 22:46:37
Solutionanalytical solutionDaniel2009-08-27 11:33:12
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