All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Progressively Geometric (Posted on 2009-09-19) Difficulty: 2 of 5
Prove that 11, 12 and 13 can never be three terms (not necessarily consecutive) of a geometric progression, irrespective of whether the common ratio is real or complex.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionA little different solutionPraneeth2009-09-20 06:27:34
SolutionCorrected Proof (spoiler)Steve Herman2009-09-20 02:24:39
Some ThoughtsFlaw in the proposed solutionSteve Herman2009-09-20 02:17:57
possible solutionDaniel2009-09-19 21:47:49
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2021 by Animus Pactum Consulting. All rights reserved. Privacy Information